Question: how we find 0.8 solve by hand written with steps CACBKC=CCCA02(1Xe)2KC=CA0XeXe2(2+CA0KC1)Xe+1=0Xe=0.80 CACBKC=CCCA02(1Xe)2KC=CA0XeXe2(2+CA0KC1)Xe+1=0Xe=0.80
CACBKC=CCCA02(1Xe)2KC=CA0XeXe2(2+CA0KC1)Xe+1=0Xe=0.80 CACBKC=CCCA02(1Xe)2KC=CA0XeXe2(2+CA0KC1)Xe+1=0Xe=0.80
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