How would you go abut this?

1) The entire graph of a one-to-one function f is given in the figure below. Let f- be the inverse of f. 3 2 1 -5 14 -3 -2 -1 1 2 3 4 -1 -2 -3 -4 a) (2 points) f-1(3) = c ) ( 2 points ) x ( 2 x - ! ) ] , - b ) ( 2 points ) ( x ) = d) Suppose f is the derivative of a function g, so f(x) = g'(x), with g continuous on the interval (-5, 4). i) (3 points) On which interval(s) is the function g decreasing? INTERVAL(s) : ii) (3 points) On which interval(s) is the function g concave up? INTERVAL(s)