Question: HW 6 Cs332 name LOGICAL ADDRESS (14 bits) STBR (binary 16 bits) MAR (binary 16 bits) 100100000 0 0 1 1 1 decimal decimal memory

 HW 6 Cs332 name LOGICAL ADDRESS (14 bits) STBR (binary 16

HW 6 Cs332 name LOGICAL ADDRESS (14 bits) STBR (binary 16 bits) MAR (binary 16 bits) 100100000 0 0 1 1 1 decimal decimal memory address TABLE MAIN MEMORY memory SEGMENT PAGE bi TABLE address 127 128 129 130 131 132 133 134 135 136 255 256 257 258 259 260 261 262 263 264 01000 01001 01010 01011 01100 01101 01110 01111 instruction 10000 10001 GIVEN THE FOLLOWING: process P5 needs to access the instruction in memory FILL IN ALL KNOWN VALUES ABOVE FOR THE FOLLOWING: WORD IS 4 BYTES STBR MAR SEGMENT TABLE PAGE TABLE FRAME SIZE IS 512 BYTES TOTAL TOTAL NUMBER OF SEGEMENTS IN THE PROGRAM IS 8 LOGICAL ADDRESS IS GIVEN (all answers in binary) 20 points HW 6 Cs332 name LOGICAL ADDRESS (14 bits) STBR (binary 16 bits) MAR (binary 16 bits) 100100000 0 0 1 1 1 decimal decimal memory address TABLE MAIN MEMORY memory SEGMENT PAGE bi TABLE address 127 128 129 130 131 132 133 134 135 136 255 256 257 258 259 260 261 262 263 264 01000 01001 01010 01011 01100 01101 01110 01111 instruction 10000 10001 GIVEN THE FOLLOWING: process P5 needs to access the instruction in memory FILL IN ALL KNOWN VALUES ABOVE FOR THE FOLLOWING: WORD IS 4 BYTES STBR MAR SEGMENT TABLE PAGE TABLE FRAME SIZE IS 512 BYTES TOTAL TOTAL NUMBER OF SEGEMENTS IN THE PROGRAM IS 8 LOGICAL ADDRESS IS GIVEN (all answers in binary) 20 points

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