Question: HW on Pointers What does the indirection operator do ? Look at the following code. int x = 7 ; int * iptr = &x;

HW on Pointers
What does the indirection operator do?
Look at the following code.
int x =7;
int *iptr = &x;
What will be displayed if you send the expression *iptr to cout? What happens if you send the expression iptr to cout?
So far you have learned three different uses for the * operator. What are they?

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