$I_1={\displaystyle \underset{-}{\overset{2}{}}}(t^2-3)(t+2)dt$

$I_2={\displaystyle \underset{-5}{\overset{2}{}}}(2t^2-t+1)(t-4)dt$

$I_3={\displaystyle \underset{0}{\overset{4}{}}}(2t^2-t+1)(2t-6)dt$

$I_4={\displaystyle \underset{0}{\overset{+}{}}}t*cos(-\frac{}{3}t)(t+1)dt$

please solve I$1,$I$2,$I$3,$I$4$