I am trying to write a function that will take in a string with numbers and return true if there are more even numbers than odd numbers and return false if there are more odd numbers.

Here is my code:

public static Boolean hasMoreEvenThanOdd(String sentence) {

int evenCount=0;

int oddCount=0;

int num;

int x=Integer.parseInt(sentence);

while(x>0) {

num=x%10;

if(num%2==0) {

evenCount++;

}else if(num%2==1) {

oddCount++;

}

x/=10;

}

return evenCount>oddCount;

}

The errors I am getting are:

Exception in thread "main" java.lang.NumberFormatException: For input string: "7 8 9 -10 11 4 6 88"

at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)

at java.base/java.lang.Integer.parseInt(Integer.java:652)

at java.base/java.lang.Integer.parseInt(Integer.java:770)

at a3.LoopsAndImages.hasMoreEvenThanOdd(LoopsAndImages.java:44)

at a3.LoopsAndImages.main(LoopsAndImages.java:10)

I am testing it with this in my main:

Boolean numbers = hasMoreEvenThanOdd("7 8 9 -10 11 4 6 88");

System.out.println(numbers);