Question: I currently writing a C++ program that calculates area, perimeter, surface area, and volume of common 2D and 3D shapes. Then, the program outputs the

I currently writing a C++ program that calculates area, perimeter, surface area, and volume of common 2D and 3D shapes. Then, the program outputs the results on the console and in a separate text file. The program takes input from a text file called Shapes.input.txt.

Input file:

SQUARE 14.5 344

SQUARE

RECTANGLE 14.5 4.65

DIMENSIONS

CIRCLE 14.5

BOX x 2 9

CUBE 13

BOX 1 2 3

CYLINDER 2.3 4 56

CANDY

SPHERE 2.4

CYLINDER 1.23

CYLINDER 50 1.23

TRIANGLE 1.2 3.2

PRISM 2.199 5

EOF

I already have the completed program with the desired output but it required to have a parsing function that I had trouble figuring out how to implement. Any help I get will be well appreciated.

Parsing function required to be used in the program:

Expected Output:

My Code:

#include  #include  #include  #include  #include  #include  #define PI 3.14159 using namespace std; int main() { ifstream in("Shapes.input.txt"); ofstream out("Shapes.output.txt"); stringstream sstr; map < string, int > shapes; string shape, line; float length, width, height, area, peri, volume; //variable declaration shapes.insert(pair("SQUARE", 1)); shapes.insert(pair("RECTANGLE", 2)); shapes.insert(pair("CIRCLE", 3)); shapes.insert(pair("TRIANGLE", 4)); shapes.insert(pair("CUBE", 5)); shapes.insert(pair("BOX", 6)); shapes.insert(pair("CYLINDER", 7)); shapes.insert(pair("PRISM", 8)); if (!in || !out) { cout << "Unable to open file(s)"; exit(1); } cout.precision(2); cout << fixed; out.precision(2); out << fixed; while (getline(in, line)) { length = width = height = 0; sstr << line; if (sstr >> shape) { switch(shapes[shape]) { case 1: //Square sstr >> length; area = length * length; peri = 4.0 * length; cout << shape << " side = " << length << " area = " << area << " perimeter=" << peri << endl; out << shape << " side = " << length << " area = " << area << " perimeter = " << peri << endl; break; case 2: //Rectangle sstr >> length >> width; area = (length * width); peri = 2.0 * (length + width); cout << shape << " length = " << length << " width = " << width << " area = " << area << " perimeter = " << peri << endl; out << shape << " length=" << length << " width = " << width << " area = " << area << " perimeter = " << peri << endl; break; case 3: //Circle sstr >> length; area = PI * (length * length); peri = 2 * PI * length; cout << shape << " radius = " << length << " area = " << area << " perimeter = " << peri << endl; out << shape << " radius = " << length << " area = " << area << " perimeter = " << peri << endl; break; case 4: //Triangle sstr >> length; area = (1.732 * length * length) / 4.0; peri = 3.0 * length; cout << shape << " side = " << length << " area = " << area << " perimeter = " << peri << endl; out << shape << " side = " << length << " area = " << area << " perimeter = " << peri << endl; break; case 5: //Cube sstr >> length; area = 6 * length * length; volume = length * length * length; cout << shape << " side = " << length << " surface area = " << area << " volume = " << volume << endl; out << shape << " side = " << length << " surface area = " << area << " volume = " << volume << endl; break; case 6: //BOX sstr >> length >> width >> height; area = 2.0 * (length * width + length * height + width * height); volume = length * width * height; cout << shape << " length = " << length << " width = " << width << " height = " << height << " surface area = " << area << " volume = " << volume << endl; out << shape << " length = " << length << " width = " << width << " height = " << height << " surface area = " << area << " volume = " << volume << endl; break; case 7: //Cylinder sstr >> length >> height; area = 2.0 * PI * length * (length + height); volume = PI * length * length * height; cout << shape << " radius = " << length << " height = " << height << " surface area = " << area << " volume = " << volume << endl; out << shape << " radius = " << length << " height = " << height << " surface area = " << area << " volume = " << volume << endl; break; case 8: //Prism sstr >> length >> height; area = 3.0 * (length * height) + (1.732 * length * length) / 2.0; volume = (1.732 * length * length * height) / 4.0; cout << shape << " side = " << length << " height = " << height << " surface area = " << area << " volume = " << volume << endl; out << shape << " side = " << length << " height = " << height << " surface area = " << area << " volume = " << volume << endl; break; default: cout << shape << " invalid object" << endl; } } sstr.str(string()); sstr.clear(); } in.close(); out.close(); return 0; }

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer

Step: 1 Unlock blur-text-image

Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock

Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!

USING VISUAL STUDIO C++ This is the first in a series of seven assignments (labs 1-4, 10, 11, 13) that will end with an object-oriented, GUI-based Windows program by the end of the semester. It...

Java Lab: In this lab you will be provided with a set of classes that exist in an inheritance hierarchy at which the top is the Shape class. You will create a class that is a collection of Shapes. It...

I need you to revise Shapes.cpp and add iShapes.cpp and iShapes.h which are following these orders. If you think there is no enough information, please ask me what types of information is missing....

The engineering division wants to have a functionality to deal with geometric 2D and 3D shapes. The user can choose to enter the measurements with different metric or imperial units and choose the...

programing C++ Description: Apply what you have learned in OOP, Inheritance, Polymorphism and Files / techniques to build the above shown Shape hierarchy. For all classes we need to store the...

Write a C + + program named Shapes . 1 . cpp to calculate area, perimeter, surface area, and volume of common 2 D and 3 D shapes. The calculations for 8 shapes include ]

Problem Solving Lab EGR-125 C++ Programming for Engineers Problem Solving and Programming Developing a program to solve an engineering problem can be accomplished using the following steps Analyze...

Hi there! One more question for you. Similar to my last one. I have to have it done by tonight. Let me know if you cannot do it. Here it is: Scenario 3 May I Propose To... You are a partner in a...

You are a partner in a prestigious accounting firm, and you just received requests for proposal from two companies; Advanced Micro Devices, and Facebook. The deadline for the proposals is, as is...

Hi there! One more question for you. Similar to my last one. I have to have it done by tonight. Let me know if you cannot do it. Here it is: Scenario 3 May I Propose To... You are a partner in a...

Presented here are the amounts of Assets, Liabilities, Shareholders Equity, Revenues, and Expenses of Camp Out, Inc. at October 31, 2013. The items are listed in alphabetical order. Accounts Payable...

What is absorption refrigeration? How does an absorption refrigeration system differ from a vapor-compression refrigeration system?

The company has declared a dividend of $ 1 . 5 5 per share. The stock goes ex dividend tomorrow. Ignoring any tax effects, what is the stock selling for today? Note: Do not round intermediate...

Flesch Corporation produces and sells two products. In the most recent month, Product C90B had sales of $21,120 and variable expenses of $5,280. Product Y45E had sales of $19,200 and variable...

7. What does managing diversity mean to you? Assume you are in charge of developing a diversity training program. Who would be involved? What would you include as the content of the program?

5. What are virtual expatriates? What are their advantages and disadvantages for the company and the manager?

4. What does the rigor of a cross-cultural training program refer to? What factors influence the level of training rigor needed?