I do not why is not correct.

Please tell me why is not correct.

The integral 1 \"/m\" dx, as in the previous questions. But with a bit of algebraic manipulation we can make it into two integrals of this form. This is because i + A = + xl x3 (xl)(x3) ' for some constantsA and B . Let's nd the value of these constants. First multiply both sides of this equation by (x 1)(x 3) . This gives A(x3)+B(x1)='1 9|. - Setting )7 = 1 in this equation means thatA = - Setting 1: = 3 in this equation means that B = . f'(x) f(x) is not in the form I Now the functions foI' % are in the required form egg) . This makes the original integral I easy to calculate as the sum of 1 - A f 1 dx = -In(x-1)/2 0 and x _ 1 . 3/ '13:: |n(x3)/2 GEE- 13