I do t get it. Why does it say "reduced number of paths" when the slit disables the current (open loop)?

*14 A student uses a strong, cylindrical magnet to investigate Lenz's law. Discuss the differences in the time taken for the magnet to fall through each tube. The student records the time taken for the magnet to fall through two hollow tubes of copper, tube A and tube B. structure and so reasoning). If there are no linkages between The two tubes have the same length and cross-sectional area. Tube B has a vertical slit arking points would yield an overall score o content and no marks for linkages). cut into it, as shown. Question Indicative content: Number Answer magnet 15(a) CI: Change in flux linkage as magnet falls (through each tube) Or (magnetic) MAX 2 for beta and 2 for gamma field lines cut the metal Beta Z EME induced (in each tube) . E Beta particles are much less massive than al TIC3: Tube(s) made of conducting material, so there is a current So beta might be deflected by the electrons rovides a closed circuit, so there is a current or Le4: Magnetic field associated with this current Beta more penetrating IC5: Upward force exerted on magnet as the field is such to oppose the change less likely to interact / scatter / defle that creates Or Or Due to Lenz's law there is a force opposing the motion of the magnet Alpha has double the charge (of beta) IC6: Magnet takes less time to fall through Tube B because the slit reduces the So for alpha deflecting force will be more (f Fotal for que Gamm sorry. what ? doesn't the slit completely Gamma isn't charged So gamma will not deflect at all (electrostat copper copper disables current flow cuz there is no closed loop? Or gamma will not experience any electros Or poor wording ? or Is there a problem w/ my . Gamma more penetrating . So gamma less likely to interact 15(b) (i) At least four straight radial lines between t concept? Equidistributed / equispaced At least one arrow pointing away from nuc Example of diagram vertical slit 15(b)(ii) Tube A Measures the distance to both potential lin Tube B Use of V = QIAREr This line is in the correct place as V x r is Obelhope 1. canent JED) Example of calculation Measures distance to 40 V = 1 cm and distand So k = 40 x 1 = 40 and k = 10 x 4 = 40 2 - curent Bo 15(b)(iii) Charge on alpha particle is 2e Use of potential difference = WiQ W = 60 (eV) Example of calculation Change in potential = 40 V -10 V = 30 V Change in potential energy = 30 V x 2e - 60 Total for question 15 12