I don't understand how my professor solved this problem. Can you please show all steps and plug in values.

PROBLEM 8: Using the diagram below we want to find the distance between reflected and refracted light d if the index of refraction of the material is 7.: 1.50, the thickness of the glass is t:3.00- cm, and the incident angle is given as , = 10.0 . deg. (a) First use Snell's law to find the angle ,, then (b) draw a triangle on the diagram that relates the variables r, d, and the incident angle . Use the relationship in (a) and (b) do find the distance d. Air GLASS n (a) 0,:=asin "(sin (8) -25.374 deg (b) d:-2 .t. tan (8,) - cos (82) -2.18 cm