I don't understand how to find ln rate using the data below. You don't have to do each trial, just ahow me Trial A so i can understand more clearly.

trial temp time : New Concentration 2000 selso horoos mo Starch and NaHSO3 Concentration (0.0038 M) V (mL) 0.002SM A B D V (mL) 5.00 5.00 5.00 5.00 5.00 5.00 5.00 5.00 5.00 S.00 5.00 s.oo 5.00 5.00 S.00 5.00 (C) 5.0 9.2 14.2 19.0 20.9 28.2 no 31.0 35.6 (s) 13.95 14.68 13.777 13.00 11.80 11.00 10.41 11.42 E F F G H H In rate A B D trial Temp (K) 170) relative rate (4) SAs) 1/1(us) 278.15 0.07168 0.003595 282.35 0.06812 0.003542 0.07262 287.35 0.07202 0.003480 292.19 0.07692 0.003423 E 294.05 0.08 475 0.003401 301.35 0.09091 10.003318 304.15 0.09606 10.003288 308.79 0.08757 0.003239 Sample calculations: Tempaa (273.15+ 5.0) K=278.15K, G H my bad I I switched them Relative rate 10.071685" Door s 13.955 2815 In rate : 0.003595 K T 278.1 SK In rate