$Ifg(x)=\frac{x}{\sqrt[\phantom{2}]{x+5}},$ find the following.

$g(0)=$

$g(4)=$

$7g(a)=$

$\frac{1}{2}g(6a)=$

$g(a^2)=$

$[g(a){]}^2=\frac{a^2}{(a+5{)}^2}$

$g(a+h)=\frac{a+h}{a+h+5}$

$g(x-a)=\frac{x-a}{x-a+5}$