Question: i ) f ( n ) = n 4 + ( log n ) 2 g ( n ) = log ( log n )

i) f(n)= n4+(log n)2 g(n)= log(log n)
ii) f(n)=2log n2 g(n)=(log n)2
iii) f(n)= n!+ n g(n)=2n
iv)()=+ log g(n)= log n2
v) f(n)=22n +10n g(n)=10nn
vi) f(n)= n! g(n)= nn
vii) f(n)=2n*2n g(n)= nn
viii) f(n)= n g(n)= log2 n
ix)()= g(n)= log n
x) f(n)=2n g(n)= n3n

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