Question: I f x [ n ] = 1 0 [ n - 1 0 ] + 1 1 [ n - 1 1 ] +

Ifx[n]=10[n-10]+11[n-11]+12
[n-12]+13[n-13]+14[n-14]
the odd part of x[n] is zero for n?
Answer:
I f x [ n ] = 1 0 [ n - 1 0 ] + 1 1 [ n - 1 1 ] +

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