Question: I have a simply supported 3 0 ' beam with a distributed load, the total load being 6 . 3 1 5 kip - ft

I have a simply supported 30' beam with a distributed load, the total load being 6.315kip-ft. there is a moment applied at x=10ft of 250 kips-ft. draw shear and moment diagrams

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!

Q:

, . , . "Consider a simply supported beam subjected to a uniformly distributed load. According to Euler - Bernoulli beam theory, how does the magnitude and distribution of this load affect the...

Q:

Figure 1 : Simply supported normal - weight concrete beam with dimensions as shown. ( a ) Draw the shear and moment diagrams considering the total self - weight of the beam and identify the maximum...

Q:

4 1 point What is the normal stress on the indicated plane in MPa ? 5 1 point What is the shear stress on the indicated plane in MPa ? What is the modular ratio n ( steel / wood ) for this beam? The...

Q:

Draw the shear - force and bending - moment diagrams for the simply supported beam below with the linearly distributed load shown below. Make sure to label your diagrams appropriately. What are the...

Q:

A simply supported wood beam carries a uniformly distributed load as shown in the figure below. a . draw the free body diagram and determine the support reactions so that the beams are in a state of...

Q:

Problem 2 A simply supported beam AB supports a linearly distributed load as shown in the figure. At point C , which is at the middle of the span, a deformable rod with length l and area A is...

Q:

The simply supported beam AE carries a uniformly distributed load with an intensity of 20 kN/m from A to B, and a concentrated load of 10 kN at point D, as shown in Figure Q2(a). The beam has the...

Q:

Use RK 4 - Kutta Method ( 1 0 points ) Example 9 . 9 . Solve d 2 y d x 2 = M E I = 3 0 x - 1 . 5 x 2 E I where E I = 1 2 1 , 5 0 0 kips - f t 2 . The boundary conditions prescribed are y ( 0 ) = 0...

Q:

1 2 3 4 5 "Consider a simply supported beam subjected to a uniformly distributed load. According to Euler - Bernoulli beam theory, how does the magnitude and distribution of this load affect the...

Q:

A simply supported beam ABCD carries a uniformly distributed load of 2 . 0 k N m between A and B , point loads of 5 k N and 6 k N at B and C respectively, and a uniformly distributed load of 7 . 0 k...

Q:

What is the purpose of a second partner review? What should be the extent of the second partners association with the engagement being reviewed?

Q:

For each pair of functions in Figure E.8 provide the values of the constants A, t0 and a in the functional shifting and/or scaling to g2(t) = Ag1(w(t-to)) Figure E.8 8. 4 4 (a) -4 -5 0 5 -5 0 10 5 10...

Q:

You are given the following information for Merrimack, Inc. Sales 240,000 Debt 80,000 Dividends 5,000 Equity 30,000 Interest rate 7% Net income 16,000 Tax rate 30% Assume the company has no...

Q:

Provide answers and explanations in detailed, thank you. 1.) Consider a principal amount of $ 1,000 to be invested at a nominal rate of 12% compounded semi annually. What would be equivalent...