I just learned calculus, so I want to be able to figure out how to solve each step. If it is a paper answer hope to be able to clear the word, but i am afraid that I will not understand the font, gratefu youl.

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Exercise 1: Differentiate and simplify: a) y = 0.2sec (esx) b) y = In(ex . sinx) 2 x_ c) V= ox d) s = 2tan3x 7x+2 e) y = log 10 . Vx f) y = 4cos x . secx 2 = In (csc y) h) y= In' (cos (Inx)) i) y= et sin'x j) y = In cos' x sin x k) y = log Vx +2 x 1) ery " = In(xy2) m) y = In sin? (Inx? ) x- n) y = log Vx2 + 1 0) 10*" = log(xy) (find dy/dx) p) y = sin 5x q) y = cos 2x* + sin'x r) z = cos* (sin 2y) s) y = tan xsec 4x cot 0 t) r= csc (30 +1) u) P = cos' \\4t-1 v) tan(x+ y) = ysinx+2 (find dy/dx) w) y = VI+csc 2x x) Find the slope of the tangent of the curve at the given point:\fdp -6cos V4t -1 sin V4t-1 21. dt V4t -1 22. V'= 1cos x - sec (x+ y) sec' (x+ y) - sin x 23. V= csc 2x cot 2x VI + csc 2x 24. 3 2 ii. -4 25. 50m / s ii. 15m / s2 26. t= 4 '4Unit 9: Derivatives of Transcendental Functions Derivatives of Trigonometric Functions [sin u] = cosul dx -[cscu]= -csc u cot u dx " [cos u] = -sin u - d dx [sec u = sec u tan u dx [tan u ] = sec' um [cot u ]=-csc' u al where u is a function of x. Derivatives of Logarithmic and Exponential Functions -[In u] = - [e" ]= e du u dx dx "[log. "]= 1 du u In b dx [ b' ] = b" In b du dx where u is a function of x