I just need c$.$

Use the worked example above to help you solve this problem. A woman of mass $m=54\mathrm{.}7kg$ sits on the left end of a seesaw$-$a plank of length $L=4\mathrm{.}53m,$ pivoted in the middle as shown in the figure.

$($a$)$ First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass $M=70\mathrm{.}4kg$ sit if the system $($seesaw plus man and woman$)$ is to be balanced?

m

$($c$)$ Repeat part $($a$),$ but this time compute the torques about an axis

through the left end of the plank.

$($C$)$ Repeat part $($a$),$ choosing a new axis through the left end of the plank.

Compute the torques using this axis, and set their sum equal to zero. Now the pivot and gravity forces on the plank result in nonzero torques.

Substitute all known quantities.

Solve for $x,$ substituting the normal force found in part $($b$).$

$|)g(\frac{L}{2})+n(\frac{L}{2})=0$

$-(75\mathrm{.}0kg)(9\mathrm{.}80\frac{m}{s^2})(2\mathrm{.}00m+x)+0$

$-(12\mathrm{.}0kg)(9\mathrm{.}80\frac{m}{s^2})(2\mathrm{.}00m)+n(2\mathrm{.}00m)=0$

$-(1\mathrm{.}47{10}^3(N)*m)-(735N)x-(235N*m)$

$+(2\mathrm{.}00m)n=0$

$x=1\mathrm{.}46m$