I$\text{'}$m attemting to implement this equation as a Java program and I've written this code. The issue is that I$\text{'}$m expecting f$($x$,$y$)=-0\mathrm{.}05769$ when I put in the command java cs$250.$ec$.$order.Equation $-2-5$ and f$($x$,$y$)=-2638\mathrm{.}46126$ for Command: java cs$250.$ec$.$order.Equation $705.$ Instead I$\text{'}$m getting f$(70\mathrm{.}0,5\mathrm{.}0)=-66273\mathrm{.}88929694473$ and f$(-2\mathrm{.}0,-5\mathrm{.}0)=-0\mathrm{.}8017837257372731.$

package cs$250.$ec$.$order;

public class Equation $\{$

$//$ Method to compute the function f$($x$,$ y$)$

public double compute$($double x$,$ double y$)\{$

$//$ Check to avoid division by zero and undefined log operations

if $($x $==0||$ y $==0)\{$

throw new IllegalArgumentException$("$x and y cannot be zero."$)$;

$\}$

$//$ Calculate the components of the equation

double absXY $=$ Math.abs$($x $*$ y$)$; $//|$xy$|$

double logXY $=$ Math.log$10($absXY$)$; $//$ log$10(|$xy$|)$

double xFourth $=$ Math.pow$($x$,4)$; $//$ x$^4$

double denominator $=$ Math.pow$($x $*$ y$,2)+$ Math.pow$($y$,3)*$ x; $//($xy$)^2+$ y$^3*$ x

$//$ Check for division by zero in the denominator

if $($denominator $==0)\{$

throw new ArithmeticException$("$Denominator is zero."$)$;

$\}$

$//$ Calculate the value of the equation

double result $=($logXY $-$ xFourth$)/$ Math.sqrt$($denominator$)$;

return result;

$\}$

public static void main$($String$[]$ args$)\{$

$//$ Check if two arguments were provided

if $($args$.$length $!=2)\{$

System.out.println$("$Usage: java cs$250.$ec$.$order.Equation $")$;

return;

$\}$

try $\{$

$//$ Parse command line arguments to double values

double x $=$ Double.parseDouble$($args$[0])$;

double y $=$ Double.parseDouble$($args$[1])$;

$//$ Create an instance of the Equation class and compute the result

Equation equation $=$ new Equation$()$;

double result $=$ equation.compute$($x$,$ y$)$;

$//$ Print the result

System.out.println$("$f$("+$ x $+","+$ y $+")="+$ result$)$;

$\}$ catch $($NumberFormatException e$)\{$

System.out.println$("$Error: Please provide valid numerical values for x and y$.")$;

$\}$ catch $($Exception e$)\{$

System.out.println$("$Error: $"+$ e$.$getMessage$())$;

$\}$

$\}$

$\}$