I need a full solution step by step, NOT A GENERAL SOLUTION!!

4) A linearly elastic bar with elastic modulus E=200GPa is composed of 3 segments and attached between two rigid walls as shown below. Each segment has a constant cross section of area A. Horizontal loads are applied at the places where the segments join. a) Using the direct finite element method, write the three element matrix equations for the standard discrete system in the form: qe=Keue, where qe is the nodal force vector for each element: qe=[qneqn+1e], where Kne is the stiffness matrix for each element: =Ke=LeEAe[1111], and where ue is the nodal displacement vector for each element: ue=[uneun+1e], Write the element matrix equations for each of the three bar elements using values and dimensional units from the attached table. [8 marks] Where A1 =600mm2,A2=400mm2,A3=120mm2 L1=200mm,L2=200mm,L3=140mm P2=1600N,P3=2000N, E=200GPa b) Assemble the full matrix equations using values and dimensional units for the standard discrete system in the form: [7 marks] qe=Keue c) Apply the boundary condition at the rigid walls and reduce the matrix equations to a set of two linear equations. [8 marks] d) Solve the matrix equations for the horizontal displacements at the two joints in the rod (where loads are applied). [7 marks]