Question: I need answer for this please 2.27 PRACTICE: Arrays : Binary to decimal conversion A binary number's digits are only 0 's and 1 's,

I need answer for this please

I need answer for this please 2.27 PRACTICE: Arrays : Binary todecimal conversion A binary number's digits are only 0 's and 1

2.27 PRACTICE: Arrays : Binary to decimal conversion A binary number's digits are only 0 's and 1 's, with each digit's weight being an increasing power of 2 . Ex: 110 is 122+121+020=14+ 12+01=4+2+0=6. A user enters an 8-bit binary number as 1 's and 0 's separated by spaces. Then compute and output the decimal equivalent. Ex: For input 00011111 , the output is: 31 (16+8+4+2+1) Hints: - Store the bits in reverse, so that the rightmost bit is in element 0 . - Write a for loop to read the input bits into an array. Then write a second for loop to compute the decimal equivalent. - To compute the decimal equivalent, loop through the elements, multiplying each by a weight, and adding to a sum. - Use a variable to hold the weight. Start the weight at 1, and then multiply the weight by 2 at the end of each iteration. \begin{tabular}{l|l} LAB \\ ACTIVITY & 2.27.1: PRACTICE: Arrays : Binary to decimal conversion \end{tabular} 0/3 Main.java Load default template

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