Question: I need description this assembly code .model small .data X db 7 Y db 4 R db ? .code .startup MOV AL,X MOV CL,5 MUL

I need description this assembly code

.model small .data X db 7 Y db 4 R db ?

.code .startup

MOV AL,X MOV CL,5 MUL CL MOV BX,AX ; X*5 IN BX MOV AL,Y MOV CL,3 MUL CL ; Y*3 IN AX SUB BX,AX ; (X*5) - (Y*3) ADD BL,X ; ((X*5) - (Y*3)+X) MOV AX,BX MOV CL,02 DIV CL MOV R,AL ;( (X*5) - (Y*3)+X)/2 HLT

End

for example:

I need description this assembly code .model small .data X db 7

I will write a description to the code I wrote line by line : Firstly I did it with taking the value of X and Y Line #1: .data (here we will define variables X and Y, note that I took the values '12' and '43' just for example try the code ) Line #2 & Line #3 :X DWORD 12 & Y DWORD 43 (here we assigned those values to the variables X and Y) Line #4: .code (this region where we will write our code ) Line #5: MOV R1,X (take the value of X and move it to the register R1 ) Line #6: MOV R2,Y (take the value of Y and move it to the register R2) Line #6: DIV R1,#3 (we devided the content of register R1 BY 3.R1 So now it contains X/3) Line #7 : DIV R2,#2 (we devided the content of register R2 BY 2.R2 SO now it contains Y/2) Line #7 : ADD R1,R2 (we added content of register R1 to the content of the register R2 so R1 now contains the value :X/3 +Y/2 Line #8 : MUL R1,R1 (we took the content of register R1 and multiplied it with herself to get the square in the equation so now R1 now contains the final value in our equation ) Line #9 :MOV R, R1 (we just copied the final value into register R as the question told us )

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