I need help drawing a mean chart to illustrate this problem.

An automatic filling machine is used to fill 1-liter bottles of cola. The machines output is approximately normal with a mean of 1.0 liter and a standard deviation of .01 liter. Output is monitored using means of samples of 25 observations. (4 points)

Determine upper and lower control limits that will include roughly 97 percent of the sample means when the process is in control.

probability = 0.97

= 0.9700 / 2 = 0.4850 where from the standard z table given Z value = 2.17

UCL = Mean + Z * (sigma/n) = 1.0 + 2.17*(0.01/25) = 1.0043

LCL = Mean - Z * (sigma/n) = 1.0 + 2.17*(0.01/25) = 0.9957

Given these sample means: 1.005, 1.001, .998, 1.002, .995, and .999, is the process in control (draw a mean chart to illustrate). No, the process is not in control because from the above control limits given sample means 1.005 and 0.995 are out of control limits.