I need help fixing my rock, paper, scissors program for Python. The code I currently have is executing functions too many times and I am getting the wrong output. I also do not know how to to write the code to use the counter code to see how many times the player wins and how many times the computer wins.

My current code is:

import random # Function: Display Menu # Input: none # Output: none # displays the game rules to the user def displayMenu(): print("Welcome! Let's play rock, paper, scissors.") print("The rules of the game are:") print("\tRock smashes scissors") print("\tScissors cut paper") print("\tPaper covers rock") print("\tIf both the choices are the same, it's a tie") # Function: Get Computer Choice # Input: none # Output: integer that is randomly chosen, a number between 0 to 2 def getComputerChoice(): computerChoice = random.randrange(0,3) return computerChoice # Function: Get Player Choice # Input: none # Output: integer that represents the choice # Asks the user for their choice: 0 for rock, 1 for paper, or 2 for scissors def getPlayerChoice(): playerChoice = int(input("Please choose (0) for rock, (1) for paper or (2) for scissors")) return playerChoice # Function: Play Round # Input: two integers--one representing the computer's choice and the other representing the player's choice # Output: integer (-1 if computer wins, 1 if player wins, 0 if there is a tie) # This method contains the game logic so it stimulates the game and determines a winner def playRound(getcomputerChoice, getplayerChoice): if getplayerChoice == 0 and getcomputerChoice == 2: return 1 elif getcomputerChoice == 0 and getplayerChoice == 2: return -1 elif getplayerChoice == 2 and getcomputerChoice == 1: return 1 elif getcomputerChoice == 2 and getplayerChoice == 1: return -1 elif getplayerChoice == 1 and getcomputerChoice == 0: return 1 elif getcomputerChoice == 1 and getplayerChoice == 0: return 1 else: return 0 # Function: Continue Game # Input: none # Output: boolean # Ask the user is they want to continue (Y/N), and then return True or False accordingly def continueGame(): playAgain = input("Do you want to continue playing? Enter (y) for yes or (n) for no.") if playAgain.lower() == "y": return True elif playAgain.lower() == "n": return False # Function: main # Input: none # Output: none def main(): displayMenu() getPlayerChoice() if getPlayerChoice() == 0: choicePlayer = "rock" elif getPlayerChoice() == 1: choicePlayer = "paper" elif getPlayerChoice() == 2: choicePlayer = "scissors" getComputerChoice() if getComputerChoice() == 0: choiceComputer = "rock" elif getComputerChoice() == 1: choiceComputer = "paper" elif getComputerChoice() == 2: choiceComputer = "scissors" print("You chose", choicePlayer + ".") print("The computer chose", choiceComputer + ".") playRound(getComputerChoice(), getPlayerChoice()) continueGame() while continueGame() == True: displayMenu() getPlayerChoice() getComputerChoice() playRound(getComputerChoice(), getPlayerChoice()) continueGame() playerCounter = 0 computerCounter = 0 tieCounter = 0 print() print("You won", playerCounter, "game(s).") print("The computer won", computerCounter, "game(s).") print("You tied with the computer", tieCounter, "time(s).") print() print("Thanks for playing!") # Call Main main()