Question: i need help, i'm really confused Assuming a normal distribution, determine the precent of data to the left of the z-score: z = 1.42 Select

i need help, i'm really confused

i need help, i'm really confused Assuming ai need help, i'm really confused Assuming ai need help, i'm really confused Assuming ai need help, i'm really confused Assuming ai need help, i'm really confused Assuming ai need help, i'm really confused Assuming a
Assuming a normal distribution, determine the precent of data to the left of the z-score: z = 1.42 Select one: O a. 92.22% O b. 91.92% O c. 93.57% O d. 90.66%Determine the z-score for the given value. # = 255, a = 40, x = 155 Select one: O a. 2 O b. -2.5 O c. 2.5 O d. 1.5 O e. -1.5 Of. -2At the end of a day at the bowling alley, three friends analyzed their scores. Mitchell's mean bowling score is 136 with a standard deviation of 17. Kris's mean bowling score is 125 with a standard deviation of 25. Dominic's mean bowling score is 149 with a standard deviation of 20. Who is the most consistent bowler? Select one: O a. Mitchell O b. Dominic O c. Not enough information to know. O d. KrisTest scores for the statistics unit exam are normally distributed with a mean score of 79% and a standard deviation of 5%. Since it's a stats test, students are given their score as a z-score. (Ha ha ha! So funny, Mr. Armstrong..) If a student received thier grade as a z-score of 3, determine the student's grade on the test. Select one: O a. 89% O b. 94% O c. 69% O d. 74% O e. 84% O f. 64%What proportion of data matches each of the following scenarios? Fizzsprockets have a mean length of 31 cm and a standard deviation of 0.4 cm. How many fizzsprockets are between 30.2 cm and 31.8 cm? Choose.. about 34.1% The mean wingspan of vultures is 1.5 m with a standard deviation of 0.1 m. How many vultures about 0.1% have a wingspan under 1.2 m? about 99.8% "Average" height at age 10 is defined as the population within one standard deviation of the about 13.6% mean. How much of the population is "average"? 100% about 95.5% about 68.2% about 50% about 2.1%Interval 70 - 74 75 - 79 80 - 84 85 - 89 90 - 94 95 - 99 100 - 104 Frequency ? ? ? ? ? ? ? Which set of data below would make the frequency table above normally distributed? Select one: O a. 18, 20, 24, 22, 23, 24, 18 O b. 3, 14, 35, 46, 33, 13, 2 O c. 46, 36, 34, 13, 12, 4, 3 O d. 35, 44, 34, 15, 3, 4, 16

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