I need help on part B

A projectile fired into the first quadrant from the origin of a coordinate system will pass 2x through the point (x,y) at time t according to the relationship cot 0 = where 0 2y + gt 2 is the angle of elevation of the launcher and g is the acceleration due to gravity (32.2 feet/second2). An artilleryman is firing at an enemy bunker located 2425 feet up the side of a hill that is 6025 feet away. He fires a round, and exactly 2.92 seconds later he scores a direct hit. . .. ." (a) What angle of elevation did he use? 0 = 23.0 (Do not round until the final answer. Then round to one decimal place as needed.) Vot (b) If the angle of elevation is also given by sec 0 = , where vo is the muzzle velocity of the weapon, find the muzzle velocity of the artillery piece he used. VO= feet/second (Round to two decimal places as needed.)