I need help on question #1, the data is given in the first picture. The molality is .296, I just don't understand how to get to that point

Summary of Data: Part 1 - Freezing Point of Cyclohexane Freezing point of pure cyclohexane: 6.4C Part 2 - Freezing Point of Acetic Acid in Cyclohexane Mass of test tube: 13.455g Mass of test tube and cyclohexane: 24.863g Mass of test tube, cyclohexane and acetic acid: 25.066g Freezing point of mixture: 3.5C Part 3 - Freezing Point of Unknown Solid in Cyclohexane Mass of test tube: 13.408g Mass of test tube and cyclohexane: 23.158g Mass of test tube, cyclohexane and unknown: 23.395g Unknown ID code (on unknown label): A van't Hoff factor for unknown (on unknown label): 1 Freezing point of unknown mixture: 2.7C From the data recorded: 1) Using the mass data, calculate the molality of the acetic acid in cyclohexane solution. molality = (moles acetic acid) / (mg C6H12) = .296