I need help, please solve in python code the folowing: Vaguely defined, B$-$spline is a collection of piecewise polynomial functions in a variable $t.$ The values of $t$ where the pieces of the

polynomial meet are known as knots denoted as $t_o,t_1,t_2,$dots,$t_m$ and sorted into increasing order.

In this project, you will write a vectorial modular program to obtain $x$ and $y$ values, which later will be used to compute a plot. You

must use logical arrays $($Boolean arrays$)$ in your solution.

With knots at $0,1,2,3$ the pieces of the uniform B$-$spline are:

$B_1=\frac{x^2}{2},0x<mn>1</mn>$

$B_2=\frac{-2x^2+6x-3}{2},1x<mn>2</mn>$

The B$-$spline function is zero outside those x ranges. YOU MUST MODIFIED THE FUNCTION BELOW APPLYING VECTORIZATION:

def Bspline$($x$)$:

$"""$

Computes Bspline piece$-$wise function

INPUT: x is scalar; OUTPUT: y is scalar

$"""$

if x$>=0$ and x:

y$=$ x$**2/2$

elif x$>=1\mathrm{.}0$ and x:

y$=(-2*$x$**2+6*$x$-3)/2\mathrm{.}0$

elif x$>=2\mathrm{.}0$ and x$<mn>3</mn><mn>.</mn><mn>0</mn>$:

y$=(3-$x$)**2/2$

else:

y$=0$ # y is zero outside x ranges.

return y