I need help plz

Problem S1. (8 points) I was changing the tire on my car and was having a hard time getting one of the bolts off; I was frustrated, but then I remembered I could use some good ole calculus to figure out how much force I need to apply to the wrench to get the bolt to move! When a force is applied to the wrench, a related force is applied to the bolt. These forces will put the wrench and the bolt under a "twisting fore", which is torque. Torque, T, is F * d where F is the the force applied and d is the distance from the center of the bolt to where the force is applied. The bolts on my car have a diameter of 10 millimeters and I chose my longest wrench for the job, which is 300 millimeters long. Luckily my wrench has a nice grip 3/4 of the way from the part that fits around the bolt for easy use. I remembered that if the sum of the torque on the wrench, 71, and the torque of the bolt, T2, is 0, then the bolt will not move. The longer I apply the force on the wrench, the more fatigued I get, and so the rate at which I am applying force to the wrench decreases, in fact the rate at which the force applied to the wrench is decreasing at 2/5 Newtons per second (N/s). At what rate is the force on the bolt changing when I am applying 40 N to the wrench and nothing is moving yet? A picture has been included for you. Remember to state your answer with units as a statement. 300 mm 1 Force applied Bolt T 2 grip5 points Save Ana Below is a picture of the second derivative of a function f, assume that ?" continues in the direction towards the Infinities. Using the graph of f", say where f is concave up and concave down. 2- 1 -2 -2 -3 f is concave up and f is concave down Type "too" and "oo" to represent negative and positive infinity; if you have multiple intervals in your answer combine them with a capital U. Moving to another question will save this