Question: i need help The mean amount spent annually on lawn service by a random sample of 97 US homeowners is $720 with a standard deviation

i need help

The mean amount spent annually on lawn service by a random sample of 97 US homeowners is $720 with a standard deviation of $123.These lawn service fees are normally distributed.How many homeowners would need to be randomly selected to construct a 95% confidence interval with a margin of error of $5?In addition to finding the sample size, show substitution into the appropriate formula.

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