i need help understanding the output below. I believe a t-test would be the correct statistical test, but then I saw equal variances assumed and I don't really understand that.

outcome looks like this:

t-test groups=Group(1,2)

/MISSING=ANALYSIS

/VARIABLES=ADS

/CRITERIA=CI(.95)

Group Statistics

Group N Mean Std Dev. Std. Error Mean

ADS face-to-face 20 9.2500 3.14350 .70291

video 20 9.0000 2.97357 .66491

Independent samples test

Levene's test for Equality of Variances

f sig t df sig. (2-tailed) mean diff. std. error diff 95% confid interval of the diff

lower upper

ads equal variances assumed .108 .744 .258 38 .798 .25000 .96757 -1.70874 2.20874

equal variances not assumed .258 37.883 .798 .25000 .96757 -1.70893 2.20893

40 participants

2-grp design w/ one population sample

same counseling model between groups

1- face2face and other video confcng

null hypothesis states no diff between scores for face2face and video confcng

Face-to-Face Counseling Video Conference Counseling

5 10

8 7

14 5

12 6

10 13

9 12

5 9

11 7

8 4

7 8

13 13

4 14

7 9

11 7

15 5

13 9

9 10

10 13

8 11

6 8

The output from the analysis is below. The results are t(38) = 0.258, p = .798.