I need help with 4 and 5 please.

The GCC compiler on CSLab translates the following C function - int func(int x){ return 13+x \} - into the following Assembly code: func: pusha \%rbp movq \%rsp, \%rbp movl \%edi, 4(%rbp) movl 4(%rbp), \%eax addl \$13, popq %rbp ret Please supply the missing operand. In the Assembly code in the previous question, suppose the value held by %rbp in after the second instruction has completed is 07ffffffe3e0 What is the address at which the parameter x is stored? Use hexadecimal notation with the 0x prefix. Omit leading 0s. Now suppose the program containing the above function func has a main function that includes the following statement: The compiler will translate this statement into the following Assembly instructions: And now suppose that the value held by \%rsp when the above two instructions are executed is 07fffffe8a0 What is the value held by \%rbp after the second instruction of func has completed? Again, use hexadecimal notation with the 0x prefix and no leading 0 s