I need help with a few answers please.

1.) Part 2-5?

Pain: A recent survey asked 826 people how many days they would wait to seek medical treatment if they were suffering pain that interfered with their ability to work. The results are presented in the following table. Number of Days Frequency 0 29 437 260 UAWNE 74 16 10 Total 826 Send data to Excel Consider these 826 people to be a population. Let \\ be the number of days for a person sampled at random from this population. Part 1 of 5 (a) Construct the probability distribution of X. Round the answer to three decimal places. 0 1 2 4 X 5 P(x) 0.035 0.529 0.315 0.090 0.019 0.012 Part: 1 / 5 Part 2 of 5 (b) Find the probability that a person would wait for 2 days. The probability that a person would wait for 2 days is ( Round the answer to three decimal places.)Part 3 of 5 (c) Find the probability that a person would wait for more than 4 days. The probability that a person would wait for more than 4 days is .( Round the answer to three decimal places.) Part: 3 / 5 Part 4 of 5 (d) Compute the mean . . Round the answer to two decimal places. Part: 4 / 5 Part 5 of 5 (e) Compute the standard deviation G. . Round the answer to three decimal places.A binomial experiment has the given number of trials n and the given success probability p. n = 8, p =0.5 Part 1 of 3 (a) Determine the probability P (1 or fewer). Round the answer to at least four decimal places. P (1 or fewer) = 0.0352 Part: 1 / 3 Part 2 of 3 (b) Find the mean. Round the answer to two decimal places. The mean isYour flight has been delayed: At Denver International Airport, 81% of recent flights have arrived on time. A sample of 10 flights is studied. Round the probabilities to at least four decimal places. Part 1 of 4 (a) The probability that all 10 of the flights were on time is 0.1216 Part: 1 / 4 Part 2 of 4 (b) The probability that exactly 8 of the flights were on time isYour flight has been delayed: At Denver International Airport, 81% of recent flights have arrived on time. A sample of 10 flights is studied. Round the probabilities to at least four decimal places. Part 1 of 4 (a) The probability that all 10 of the flights were on time is | 0.1216 Part: 1 / 4 Part 2 of 4 (b) The probability that exactly 8 of the flights were on time is Part: 2 / 4 Part 3 of 4 (c) The probability that 8 or more of the flights were on time is Part: 3 / 4 Part 4 of 4 (d) It (Choose one) be unusual for 9 or more of the flights to be on time since the X 5 probability is