I need help with the following please.

Section 10.7: Problem 13 Previous Problem Problem List Next Problem (1 point) Consider the following series: E 4 . 8 . 12 .. . (4n) 2 - 9 - 16 .. . (7n - 5) Find the radius of convergence R. R = #: (Enter "infinity" if the radius is infinite.) Section 10.7: Problem 15 Previous Problem Problem List Next Problem (1 point) Consider the following series: Find the interval of convergence. The series converges if a is in #: (Enter your answer using interval notation.) Within the interval of convergence, find the sum of the series as a function of z. If ar is in the interval of convergence, then the series converges to: Section 10.7: Problem 17 Previous Problem Problem List Next Problem (1 point) Consider the following series: 1 - 1 ( 2 - 7 ) + 2 ( 2 - 7) 2 + ...+ ( - 1 ) ( 2 - 7)"+... Find the interval of convergence. The series converges if x is in # (Enter your answer using interval notation.) Within the interval of convergence, find the sum of the series as a function of r. If ax is in the interval of convergence, then the series converges to: Find the series obtained by differentiating the original series term by term. The new series is) n=0 (Since this sum starts at n = 0, be sure that your terms are of the form C., " so as to avoid terms including negative exponents.) Find the interval of convergence of the new series. The new series converges if x is in # (Enter your answer using interval notation.) Within the interval of convergence, find the sum of the new series as a function of r. If x is in the interval of convergence, then the new series converges to: Find the series obtained by integrating the original series term by term. The new series is) Find the interval of convergence of the new series. The new series converges if I is in !! (Enter your answer using interval notation.) Within the interval of convergence, find the sum of the new series as a function of r. If I is in the interval of convergence, then the new series converges to