I need help with these question from physics. I decided to take on an extra practice worksheet to study but I'm stuck. Please solve and explain the questions below. Everything is given in the attachments, thanks!!

Coulomb's Law HWK (Solve on another sheet of paper, show generic equations, show all calculations, box answer, and attach to this assignment) 1. Two point charges, QA = +8 JC and QB = -5 JC, are separated by a distance r = 10 cm. What is the magnitude of the electric force? A 10 cm Known : Charge A (q ) = +8 JC = +8 x 10-6 C Charge B (qB) = -5 JC = -5 x 106 C k = 9 x 109 Nm2C-2 The distance between charge A and B (AB) = 10 cm = 0.1 m Answer: 4 x 10-9 N 2. Three charged particles are arranged in a line as shown in figure below. Charge A = -5 JC, charge B = +10 JC and charge C = -12 JC. O A 6 cm B 4 cm Known : Charge A (qA) = -5 JC = -5 x 10-6 C Charge B (qB) = +10 JC = +10 x 10-6 C Charge C (qc) = -12 JC = -12 x 106 C k = 9 x 109 Nm2C-2 The distance between particle A and B (AB) = 6 cm = 0.06 m = 6 x 10-2 m The distance between particle B and C (BC) = 4 cm = 0.04 m = 4 x 10-2 m a) Find the magnitude and the direction of net electrostatic force on particle A Answer: 71 N Rightward b) Find the magnitude and the direction of net electrostatic force on particle B Answer: 550 N Rightward 3. +Q1 = 10 HC, +Q2 = 50 JC and Q3 = +90uC are separated as shown in the figure below.Known : Charge 1 (q1) = +10 \"C = +10 x1015 C Charge 2 (q2) = +50 pC = +50 x10'6 C Charge 3 (q3) = +90 pC = +90 x10'5 C The distance between charge 1 and 2 (r12) = 2 cm = 0.02 m = 2 x 10'2 m The distance between charge 2 and charge 3 (r23) = 6 cm = 0.06 m = 6 x 10'2 m a) Find the magnitude and the direction of net electrostatic force on particle 2 Answer: 0 N (no direction) b) Find the magnitude and the direction of net electrostatic force on particle 1 Answer: 12,516 N Leftward