I need help with this FRQ. Would you please solve this question and show the way how you solved it?

-6 f(x) = x3 + 2 fix] = -3x+12 -2 0 -w Let R be the region bounded by f (ac) = a2 + 2, y = -3x + 12, the x-axis, and the y-axis. Assume that the axes are measured in centimeters. a. Find the area of region R. b. If the region R is the base of a solid and each cross-section perpendicular to the x-axis is a square, write, but do not evaluate, an expression involving one or more integrals that gives the volume of the solid. c. Write, but do not evaluate, an expression involving one or more integrals to find the volume of the solid generated by rotating the region R about the y-axis