I need help with this in Python.

Use Python for-loops to solve the following cryptogram SEND +MORE MONEY Each letter stands for a different digit. You can solve this puzzle the way it is intended to be solved, by deduction and some trial and error. For example, the value of M needs to be one since the sum of two four-digit numbers starts at best with a 1. You need to write a series of nested for loops. To not have the program iterate through all 10' possibilities, you can use "continue" to move the execution of the enclosing loop to the next iteration value You also should write a function carry with a variable number of arguments that calculates the carry of the numbers. For example carry (9, 8, 7,6) should be 3. Here is how my solution starts def carry (*numbers): return sum (numbers)//10 def solve () for s in range (1,10): for e in range (10): If e=-s : continue for n in range (10): continue for d in range (10): Use Python for-loops to solve the following cryptogram SEND +MORE MONEY Each letter stands for a different digit. You can solve this puzzle the way it is intended to be solved, by deduction and some trial and error. For example, the value of M needs to be one since the sum of two four-digit numbers starts at best with a 1. You need to write a series of nested for loops. To not have the program iterate through all 10' possibilities, you can use "continue" to move the execution of the enclosing loop to the next iteration value You also should write a function carry with a variable number of arguments that calculates the carry of the numbers. For example carry (9, 8, 7,6) should be 3. Here is how my solution starts def carry (*numbers): return sum (numbers)//10 def solve () for s in range (1,10): for e in range (10): If e=-s : continue for n in range (10): continue for d in range