Question: i need help with this question ASAP Consider the following C program. main int a; short b; char c; double d; int . pint -8a;

i need help with this question ASAP i need help with this question ASAP Consider the following C program.

Consider the following C program. main int a; short b; char c; double d; int . pint -8a; short pShort - 8b char Char - &c; double pDouble - &d; printf(p Sop so ", pChar, Short, Int, pouble); // line 4 printf(pp on pChar+1, pShort+1, Int+1, pDouble-1); // line 5 pint++; pShort++pChar ++; pDouble +: pint + 4; Short pChar +4; Double +-4; printf("poso", pChar+1, pShort+1, pint+1, pouble+1); // line 8 > Suppose the output of the first printf (line 4) is 3200 5600 7000 8000 (Recall that printing a pointer with %p outputs the content/value of the pointer, which is the address of its pointee, in Hex. To simplify, here we assume it prints in decimal) Assume short, int and double takes 2, 4 and 8 bytes respectively. What is the output of the program in line 5 and line 8 (in decimal)? c? ! o o US Xzx 7 A- I- B line5: line 8

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