I need help with this question

In the diagram below, if 3 BF = 2FC, AE = 2EF, and [DEF] = 1, then what is [ ABC]. A D E 1 B C Let [ BEF] = x. AE = 2EF = [ADE] = and { A BE] = x (by the Fixed Height Triangle Theorem case 2). CF =( )BF [CDF] =( [BDF] =( )(x + 1), and CF = BF [ACF] = (give your answer in alphabetical order). This gives an equation of x, solve to get that x = and hence [ ABC] = (Give your answer as a reduced fraction.)