I need help with this question.

Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribution with a mean of 24 square feet and a standard deviation of 6 square feet. (a) What is the probability that the area covered by a can of spray paint is more than 26 square feet? (Round your answer to four decimal places.) (b) Suppose you want to spray paint an area of 260 square feet using 10 cans of spray paint. On average, how many square feet must each can be able to cover to spray paint all 260 square feet? (Enter your answer as a whole number.) (c) What is the probability that you can cover a 260 square feet area using 10 cans of spray paint? (Round your answer to four decimal places.) (d) If the area covered by a can of spray paint had a slightly skewed distribution, could you still calculate the probabilities in parts (a) and (c) using the normal distribution? We could not " . calculate (a) without a nearly normal population distribution. Without a nearly normal population distribution and a small sample size of n = 10, the sampling distribution |will not be nearly normal. Therefore we could not * . calculate (c) either