Question: i need part e and F to be done only pls 7. Given the Boolean Statement: X=[A(B+C)][BC] + A (B+C) (a) Draw a Circuit Diagram
i need part e and F to be done only pls

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7. Given the Boolean Statement: X=[A(B+C)][BC] + A (B+C) (a) Draw a Circuit Diagram for the X. (b) Create a truth table for X. (C) Get an expression for X form the truth table created in part (b). (d) Simplify the expression obtained in part (c) using Karnaugh Map. Simplify X (original expression) using Laws of Boolean Algebra. (e) (f) Simplify the expression obtained in part (c) using Laws of Boolean d. given Booleen expressin @ A 18+) ABC + A (B) B A & A 0 Truth Table Truth Table A 8 c Btc + BTC A(6+) Alste) ABC AC8+) X 0 0 1 0 0 0 0 1 I + 0 O 1 1 1 o 0 9 O 0 0 0 1 G ! 1 0 0 ! 0 0 1 o o o 0 o 0 0 0 O O 1 1 0 0 o X Houtput Xe ABC + ABC + ABC + A5C + ABC +ABC 0 wing K-map bi ic BL BE A I POL -group-t a A perp-2 AB grerep-3 Bc Xi = AT +AB+ 8C
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