I need solve this

Use a comparison test to determine whether the integral converges or diverges. Determine whether the integral converges or diverges. If it converges, determine its value. So sin (20x) -dx 2 9 + ex q12 dx -00 3(1 + x2) q13 Comparing to sin6(20x) dx, the integral converges. The integral converges to WIN The integral converges to 7. 00 Comparing to sin6(20x) dx, the integral diverges. The integral converges to 2.6. The integral converges to - Comparing to _dx, the integral diverges. Comparing to -dx, the integral converges