I need some practice with these problems in Physics. I'm taking some extra work so I can study so I'm using a few practice problems. Please show the work so I can study it!! Please include all the work states. The photos are where the questions are Refer to the photos below to answer, thanks!!

What is the best version of the conservation of momentum equation to use for this scenario? * A. m,Vi+m,V2 = m,V,'+m2V2' B. m,Vi+m2V2= (m,+m2) V C. (m,+m2) V = m,Vj'+m2V2' D. ml+v1+m2+v2=ml+v1'+m2+v2' O A O B O C OD T or F: The total momentum of the system is zero before and after the interaction * True False T or F: In order to isolate mass 2, the momentum of mass 1 must be subtracted to the other side of the equation. * True False What is the value of mass 2? * 3.6 kg 5.0 kg 5.9 kg 7.1 kg 12 kgAnswer the following questions based on the scenario: Two masses are initially at rest on a horizontal friction-less surface. One mass is 5 kg and the other mass is unknown. A light spring is compressed between the bodies. After the spring is released, the 5 kilogram body has a speed of 0.2 m/s right. The speed of the unknown mass is 0.14 m/s left. What is the unknown mass? What is this type of interaction? 1 point O Elastic Collision Perfectly Inelastic Collision O Separating Body O Cannot be determined from description The correct set of givens are... 2 points A Mass 1 Mass 2 m1 = 5 kg m2 =? V1 = -0.2 m/s V2 = -0.14 m/s V1' = 0 m/s V2' = 0m/s B. Mass 1 Mass 2 m1 = 5 kg m2 = /1 = 0.2 m/s V2 = -0.14 m/s V =? C. Mass 1 Mass 2 m1 = 5 kg m2 =? V =0m/s V1' = 0.2 m/s V2' = 0.14 m/s D. Mass 1 Mass 2 m1 = 5 kg m2 =? V =0m/s V1' = 0.2 m/s V2' = -0.14 m/s O A O B O C OD