9 mol P4010 reacts with 51 mol HO according to the equation below: P4010 + 6HO...
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9 mol P4010 reacts with 51 mol H₂O according to the equation below: P4010 + 6H₂O → 4H3PO4 How many moles of H3PO4 form from 9 mol P4010? [?] mol H3PO4 Round your answer to the ones place. mol H₂PO Enter 9 mol P4010 reacts with 51 mol H₂O according to the equation below: P4010 + 6H₂O → 4H3PO4 How many moles of H3PO4 form from 9 mol P4010? [?] mol H3PO4 Round your answer to the ones place. mol H₂PO Enter
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