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Hence, the total pressure of the system is: P=19679Pa+751.5torrx133.3(Pa/torr)=119854 Pa The question requires the answer in units of kPa, and hence we write 120 kPa Q2) A closed end manometer was attached to a vessel containing argon. The difference in mercury levels in the two arms of the manometer was 12.2 cm. Atmospheric pressure was 783 mmHg. What was the pressure of the argon in the container, in mmHg? h = 12.2 dm o.122 m Pasn= 783 multy P= ? Hg (a) 882 loo (b) 661 122