5.11 A small sharp crested triangular weir with a half angle (0/2) of 15 is calibrated...

  

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5.11 A small sharp crested triangular weir with a half angle (0/2) of 15° is calibrated in a laboratory. The actual discharge, QA, over the weir is measured by collecting a known mass (M) of water in a time, T. The corresponding head over the weir crest, H, is as shown below. (a) Plot a graph of QA against H5/2 and use it to calculate the average value of the coefficient of discharge. (b) Plot a graph of log QA against log H and use it to evaluate (i) the expo- nent of the discharge equation; (ii) the constant of the discharge equation; and (iii) the corresponding coefficient of discharge. [(a) 0.64; (b) (i) 2.41; (ii) 0.317 so QA = 0.317H2.41; (iii) 0.50] M (kg) 30 15 7.5 15 7.5 T (s) 45.2 36.7 34.6 93.8 96.2 H (m) 0.0769 0.0638 0.0488 0.0430 0.0320 5.11 A small sharp crested triangular weir with a half angle (0/2) of 15° is calibrated in a laboratory. The actual discharge, QA, over the weir is measured by collecting a known mass (M) of water in a time, T. The corresponding head over the weir crest, H, is as shown below. (a) Plot a graph of QA against H5/2 and use it to calculate the average value of the coefficient of discharge. (b) Plot a graph of log QA against log H and use it to evaluate (i) the expo- nent of the discharge equation; (ii) the constant of the discharge equation; and (iii) the corresponding coefficient of discharge. [(a) 0.64; (b) (i) 2.41; (ii) 0.317 so QA = 0.317H2.41; (iii) 0.50] M (kg) 30 15 7.5 15 7.5 T (s) 45.2 36.7 34.6 93.8 96.2 H (m) 0.0769 0.0638 0.0488 0.0430 0.0320

Answer rating: 100% (QA)

To calculate the coefficient of discharge you can follow these steps a Plot a graph of QA against H5... View the full answer