I need this project done in Python, I run my code in Anaconda

a$)$ Calculate the electric field vec$(E)(x,y)$ of a dipole with charge $q$ and distance $d$ at any point in

the plane that contains the charges. Remember that the electric field due to a point charge

is

vec$(E)(vec(r))=k\frac{q}{r^2}$hat$(r)=k\frac{q}{r^2}\frac{(vec(r))}{r}=k\frac{q}{r^3}$vec$(r),$

with $k=9{10}^9\frac{N{m}^2}{C^2}.$ In this project we will calculate the electric field in the $xy-$plane only.

In your calculations, set the positive charge at the position $(0,\frac{d}{2})$ and the negative charge

at $(0,-\frac{d}{2}).$ Therefore, the electric field in cartesian coordinates at any point $(x,y)$ due to the

positive point charge $q$ is

vec$(E)(x,y)=k\frac{q}{r^3}$xhat$()+k\frac{q}{r^3}(y-\frac{d}{2})hat()$

with $r=\sqrt[\phantom{2}]{x^2+(y-\frac{d}{2}{)}^2}.$

The electric field at any point $(x,y)$ due to the negative point charge $q$ is

vec$(E)(x,y)=k\frac{(-q)}{r^3}$xhat$()+k\frac{(-q)}{r^3}(y+\frac{d}{2})hat()$

with $r=\sqrt[\phantom{2}]{x^2+(y+\frac{d}{2}{)}^2}.$

b$)$ Use the pylab function streamplot$()$ to display the electric field lines on the plane that

contains the charges. Use $q=3nC$ and $d=10cm.$ Display the field lines with $x$ and $y$ ranging

from $-30cm$ to $30cm.$

c$)$ Calculate the electric potential $V(x,y)$ of a dipole with charge $q$ and distance $d$ at any point in

the plane that contains the charges. Remember that the electric potential due to a point

charge $q$ is

$V(r)=k\frac{q}{r}$

For the positive charge

$V(x,y)=k\frac{q}{\sqrt[\phantom{2}]{x^2+(y-\frac{d}{2}{)}^2}}$

For the negative charge

$V(x,y)=k\frac{(-q)}{\sqrt[\phantom{2}]{x^2+(y+\frac{d}{2}{)}^2}}$