Question: I noticed while testing my C++ contact manager that when the phone number entered is not an integer the program displays all of the cout
I noticed while testing my C++ contact manager that when the phone number entered is not an integer the program displays all of the cout statements over and over without stopping. I can't figure out what if statement to use to check for an integer. Here is the code i have so far:
#include
#include
#include
using namespace std;
// Declaring Global Arrays
string names[10];
long long phoneNos[10];
// Function Declarations
void getData();
void sort();
void display();
long long searchPhoneNum();
int main()
{
// Declaring variables
int choice;
/* This while loop continues to execute
* until the user enters a valid menu option
*/
while (true)
{
cout << "********Menu*********" << endl;
cout << "1.Add Contact" << endl;
cout << "2.Display All Conacts" << endl;
cout << "3.Search Contacts" << endl;
cout << "4.Exit" << endl;
cout << "****Enter Choice:****"<< endl;
cin >> choice;
/* Based on the Menu option selected
* the corresponding case will be executed
*/
switch (choice)
{
case 1:
{
// Calling the get data functions to store data
//Need to figure out if I need an IF statement here when phone number is //not an integer
getData();
continue;
}
case 2:
{
// Calling the sort and display functions
sort();
display();
continue;
}
case 3:
{
// Calling the search for phone number functions
long long no = searchPhoneNum();
if (no != -1)
cout << "The Telephone number is :" << no << endl;
else
cout << "~Sorry, no contact found~" << endl;
continue;
}
case 4:
{
cout << "** Good Bye **" << endl;
break;
}
default:
{
cout << "!!!!!!!!!!!!!!!!!!!!!!!!!" << endl;
cout << "!!Invalid Menu Option!!" << endl;
cout << "!!!!!!!!!!!!!!!!!!!!!!!!! << endl;
continue;
}
}
break;
}
return 0;
}
/* Function implementation which will
* get the data from the user and populate
* the data into arrays. Case 1
*when testing this entering alpha characters
*all of the cout statements repeat to no end
*need to add a condition that if the phone number
*entered is not an integer, it loops back to enter phone
*number while keeping the stored # matching the name
*/
void getData()
{
string name;
long long phNo;
for (int i = 0; i < 10; i++)
{
cin.ignore();
cout << "Enter name of Person#" << i + 1 << ":";
std::getline(std::cin, name);
names[i] = name;
cout << "Enter Phone Number:";
cin >> phNo;
phoneNos[i] = phNo;
}
}
/* Function implementation which will
* which will sort the data in the arrays. Case 2 part 1
*/
void sort()
{
// This Logic will Sort the Array of elements in Ascending order
string tempName;
long long tempNum;
for (int i = 0; i < 10; i++)
{
for (int j = i + 1; j < 10; j++)
{
if (phoneNos[i] > phoneNos[j])
{
tempNum = phoneNos[i];
phoneNos[i] = phoneNos[j];
phoneNos[j] = tempNum;
tempName = names[i];
names[i] = names[j];
names[j] = tempName;
}
}
}
}
/* Function implementation which will
* search the phone number in the arrays. Case 3
*/
long long searchPhoneNum()
{
string name;
cin.ignore();
cout << "Enter the name :";
std::getline(std::cin, name);
int i = 0;
while (i < 10)
{
if (name.compare(names[i]) == 0)
{
return phoneNos[i];
}
i++;
}
return -1;
}
/* Function implementation which will
* display the data in the arrays. Case 2 part 2
*/
void display()
{
cout << "^^Here are your Contacts^^ " << endl;
for (int i = 0; i < 10; i++)
{
cout << setw(10) << names[i] << "\t\t" << phoneNos[i] << endl;
}
}
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