Question: I Only need Question 4 and 5 Use the Excel output in the below table to do (1) through (6) for each of 80, 61,

I Only need Question 4 and 5

I Only need Question 4 and 5 Use the Excel output inthe below table to do (1) through (6) for each of 80,

Use the Excel output in the below table to do (1) through (6) for each of 80, 61, 62, and 63. y = 60 + 61*1 + 62x2 + 83X3 + = df = n - (k + 1) = 16 - (3 + 1) = 12 Excel output for the hospital labor needs case (sample size: n = 16) Coefficients Standard Error t Stat p-value Lower 95% Upper 95% Intercept 1946. 8028 504. 1819 3.8613 9. 0923 848 . 2848 3845. 3201 XRay (x1) 0.0386 0.0138 2.9579 9.0129 e. 6102 8. 0678 BedDays (x2) 1.9394 0.0676 15.3857 2.91E-09 9.8922 1. 1856 LengthStay (x3) -413.7578 98. 5983 -4.1964 9. 9812 -628.5850 -198.9306 (1) Find by. sby. and the t statistic for testing Me: 6. = e on the output and report their values. (Round your t value answers to 3 decimal places and other answers to 4 decimal places. Negative values should be Indicated by a minus sign.) bj sbj t HO: 80 = 0 1,046.8020 604.1819 3.861 HO: 81 = 0 0.0386 0.0130 2.969 HO: 82 = 0 1.0394 0.0876 15.376 HO: 83 = 0 (413.7578) 98.5083 4.196) (2) Using the t statistic and appropriate critical values, test Ng: 6% = 0 versus My: 6% > @ by setting a equal to .05. Which independent variables are significantly related to y in the model with d =.05? (Round your answer to 3 decimal places.) 1.025 2.131 HO: 80 = 0; Do not reject HO HO: 81 = 0; Do not reject HO HO: 82 = 0; Do not reject HO HO: 83 = 0; Do not reject HO(4) Find the p-value for testing My: 8, =@ versus Hy: 6, # @ on the output. Using the p-value, determine whether we can reject Ho by setting a equal to .10. .05. .01, and .001. What do you conclude about the significance of the independent variables in the model? (Round your answers to p-value at 8 2 = 0 and 83 = 0 to 4 decimal places. Round other answers to 3 decimal places.) HO: 81 = 0 is : Reject HO at o = HO: 82 = 0 is Reject HO at o = HO: 83 = 0 is : Reject HO at 0 = (5) Calculate the 95 percent confidence interval for 6,, (Round your answers to 3 decimal places. Negative values should be Indicated by a minus sign.) 95% C.I. 80 81 B3

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