Question: I only require the answer to see my own work is correct Find an equation for the line tangent to given curve 23y _ y?

I only require the answer to see my own work is correct

Find an equation for the line tangent to given curve 23y _

$= :1: 1 \fIf y = ln(:z:2 + y2) then the value$ of 33 at the point (1,0) is Select one: 0 a. 0

Find an equation for the line tangent to given curve 23y _ y? = 1 at :1: = 1. Select one: C) a. y = :1: 1 \fIf y = ln(:z:2 + y2) then the value of 33 at the point (1,0) is Select one: 0 a. 0 O b. 1/2 0 c. 'l 0 d. 2 0 e. undefined

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