Question: I performed a simple circuit experiment using three resistors. What formula do I use to find the measured potential difference (V) in this case? Note:

I performed a simple circuit experiment using three resistors. What formula do I use to find the measured potential difference (V) in this case?

I performed a simple circuit experiment using three resistors. What formula do

Note: Uncertainty in resistance can be calculated by the following formula: OR = (OR OV ) + (OR 81 ) Here, R - total resistance = . For calculus-based students, calculate the uncertainty in each total resistance based on the uncertainties in current and voltage measurements. For algebra- based students, have your TA calculate this for you. . /. diff = 1 1, 118.8 - 1, 114.71 x 100 = 0. 34./ . 1 , 118.8 V= IR XMeasured potential difference (V) = SR = ( V)2 + ( I) 1. Series 8 R = (5005)+10.00449)2 Theoretical total resistance (R) = 1 118 .8 ohms Reg= R, + Ra 8R= 5.005 Measured current (1) = 0. 00 479 + 5.005 amps Reg= 559.4 + 559.4= 1, 118.8 Measured total resistance (Rum) = 1,I1 4 . 7 + 5.005 ohms = = 5.005- 0. 00449 - Percent difference between theoretical and measured resistance 0. 3 4./. 1, 114.7 2. Parallel Req= R,. R2 - 559. 4x559.4 279 . 7 ohms Rit R 2 2 559-4+ 559-4 Theoretical total resistance (R) =279.7 Measured current (1) = 0.0179 2 + 5.005 amps Measured total resistance (R.) = 271 - 3+ 5.005 ohms I 1= v = 5.005 =279.3 0. 01792 Percent difference between theoretical and measured resistance 0. 14 . 1 . Rp t Ron ./. diff= /279.7- 279. 31 X 100 . / 279.7 8 R = 1 ( V ) 2 + ( I ) 2 137 = 0.14 OR = (5.005)2 + (0.01792)2= 5.005

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